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	<title>Comments on: What Are The Odds Of Getting A Pair Of Aces Before The Flop In Texas Holdem?</title>
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		<title>By: Zippy</title>
		<link>http://pokerasdf.com/what-are-the-odds-of-getting-a-pair-of-aces-before-the-flop-in-texas-holdem/comment-page-1#comment-2085</link>
		<dc:creator>Zippy</dc:creator>
		<pubDate>Mon, 01 Mar 2010 06:04:40 +0000</pubDate>
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		<description>depends on the number of players, but if i were to guess I&#039;d say one in 50</description>
		<content:encoded><![CDATA[<p>depends on the number of players, but if i were to guess I&#8217;d say one in 50</p>
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		<title>By: sincity usa</title>
		<link>http://pokerasdf.com/what-are-the-odds-of-getting-a-pair-of-aces-before-the-flop-in-texas-holdem/comment-page-1#comment-2084</link>
		<dc:creator>sincity usa</dc:creator>
		<pubDate>Mon, 01 Mar 2010 04:41:11 +0000</pubDate>
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		<description>1/221 hands and you ony have a scant chance of making a set</description>
		<content:encoded><![CDATA[<p>1/221 hands and you ony have a scant chance of making a set</p>
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		<title>By: James O only logical answer  D</title>
		<link>http://pokerasdf.com/what-are-the-odds-of-getting-a-pair-of-aces-before-the-flop-in-texas-holdem/comment-page-1#comment-2083</link>
		<dc:creator>James O only logical answer  D</dc:creator>
		<pubDate>Mon, 01 Mar 2010 01:17:43 +0000</pubDate>
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		<description>The odds are 220-1. So every 220 hands you will on average get a pair of aces in the hole. Now i have had times where i went 500-600 hands without aces, or i have had times where i have had aces on back to back hands, but the average is 220-1.</description>
		<content:encoded><![CDATA[<p>The odds are 220-1. So every 220 hands you will on average get a pair of aces in the hole. Now i have had times where i went 500-600 hands without aces, or i have had times where i have had aces on back to back hands, but the average is 220-1.</p>
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		<title>By: Joanne</title>
		<link>http://pokerasdf.com/what-are-the-odds-of-getting-a-pair-of-aces-before-the-flop-in-texas-holdem/comment-page-1#comment-2082</link>
		<dc:creator>Joanne</dc:creator>
		<pubDate>Sun, 28 Feb 2010 18:27:15 +0000</pubDate>
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		<description>4/52 * 3/51 = .004524887 or 1 chance in 220.999</description>
		<content:encoded><![CDATA[<p>4/52 * 3/51 = .004524887 or 1 chance in 220.999</p>
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		<title>By: duke5098</title>
		<link>http://pokerasdf.com/what-are-the-odds-of-getting-a-pair-of-aces-before-the-flop-in-texas-holdem/comment-page-1#comment-2081</link>
		<dc:creator>duke5098</dc:creator>
		<pubDate>Sun, 28 Feb 2010 15:55:09 +0000</pubDate>
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		<description>Yes, The three previous answers are correct. About 1 in 221. Also, it really doesn&#039;t matter how many people are playing.</description>
		<content:encoded><![CDATA[<p>Yes, The three previous answers are correct. About 1 in 221. Also, it really doesn&#8217;t matter how many people are playing.</p>
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		<title>By: forgiveb</title>
		<link>http://pokerasdf.com/what-are-the-odds-of-getting-a-pair-of-aces-before-the-flop-in-texas-holdem/comment-page-1#comment-2080</link>
		<dc:creator>forgiveb</dc:creator>
		<pubDate>Sun, 28 Feb 2010 15:11:49 +0000</pubDate>
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		<description>.45 % or 222 to 1</description>
		<content:encoded><![CDATA[<p>.45 % or 222 to 1</p>
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		<title>By: Anonymous</title>
		<link>http://pokerasdf.com/what-are-the-odds-of-getting-a-pair-of-aces-before-the-flop-in-texas-holdem/comment-page-1#comment-2079</link>
		<dc:creator>Anonymous</dc:creator>
		<pubDate>Sun, 28 Feb 2010 10:54:05 +0000</pubDate>
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		<description>The same as the odds of getting ANY pair.  
What are the chances of getting the FIRST ace?
4 out of 52 cards.      
What are the chances of getting the SECOND ace?
3 out of 51 cards.
Do the math.
(51 x 52) divided by ( 3 x 4)
2652 divided by 12  or 1 chance in 221  or 0.45%</description>
		<content:encoded><![CDATA[<p>The same as the odds of getting ANY pair.<br />
What are the chances of getting the FIRST ace?<br />
4 out of 52 cards.<br />
What are the chances of getting the SECOND ace?<br />
3 out of 51 cards.<br />
Do the math.<br />
(51 x 52) divided by ( 3 x 4)<br />
2652 divided by 12  or 1 chance in 221  or 0.45%</p>
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