The same as the odds of getting ANY pair.
What are the chances of getting the FIRST ace?
4 out of 52 cards.
What are the chances of getting the SECOND ace?
3 out of 51 cards.
Do the math.
(51 x 52) divided by ( 3 x 4)
2652 divided by 12 or 1 chance in 221 or 0.45%
The odds are 220-1. So every 220 hands you will on average get a pair of aces in the hole. Now i have had times where i went 500-600 hands without aces, or i have had times where i have had aces on back to back hands, but the average is 220-1.
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7 Responses
Anonymous
February 28th, 2010 at 10:54 am
1The same as the odds of getting ANY pair.
What are the chances of getting the FIRST ace?
4 out of 52 cards.
What are the chances of getting the SECOND ace?
3 out of 51 cards.
Do the math.
(51 x 52) divided by ( 3 x 4)
2652 divided by 12 or 1 chance in 221 or 0.45%
forgiveb
February 28th, 2010 at 3:11 pm
2.45 % or 222 to 1
duke5098
February 28th, 2010 at 3:55 pm
3Yes, The three previous answers are correct. About 1 in 221. Also, it really doesn’t matter how many people are playing.
Joanne
February 28th, 2010 at 6:27 pm
44/52 * 3/51 = .004524887 or 1 chance in 220.999
James O only logical answer D
March 1st, 2010 at 1:17 am
5The odds are 220-1. So every 220 hands you will on average get a pair of aces in the hole. Now i have had times where i went 500-600 hands without aces, or i have had times where i have had aces on back to back hands, but the average is 220-1.
sincity usa
March 1st, 2010 at 4:41 am
61/221 hands and you ony have a scant chance of making a set
Zippy
March 1st, 2010 at 6:04 am
7depends on the number of players, but if i were to guess I’d say one in 50
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Welcome at Pokerasdf! Find your poker infomation. We listed some intresting books for you to read here! Also if you have some poker questions you can see some poker questions and answers here!
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